Python eval in def with passed in func: map okay but list comprehension fails on namespace -

i trying grasp nuances of python namespaces. why eval() on list comp fail when enclosed func passed function containing eval? of these run2x versions work except last 1 run2g.

def sub2(var2):     var2 += 1     return var2  def run2c():  # works retrieving sub2 globals     print('comp', eval('[sub2(n) n in (1,2,3)]'))  def run2h(func):  # partial fix cannot access globals in eval()     print('arg comp', eval('[func(n) n in (1,2,3)]', locals()))    def run2h(func):  # fails again on func     print('arg comp', eval('[func(n) n in (1,2,3)]', globals(), locals()))  def run2g(func):  # fails use func in locals     print('arg comp', eval('[func(n) n in (1,2,3)]'))  # nameerror: name 'func' not defined     def run2a():     print('base', eval('sub2(1)'))  def run2b():     print('map', list(eval('map(sub2, (1,2,3))')))  def run2c_():     print('comp', eval('[sub2(n) n in (1,2,3)]'))  def run2d(func):     print('arg', eval('func(1)'))  def run2e(func):     print('arg map', list(eval('map(func, (1,2,3))')))  def run2f(func):     print('arg plain', [func(n) n in (1,2,3)])  def run2g_(func):     print('arg comp', eval('[func(n) n in (1,2,3)]'))  # nameerror: name 'func' not defined    if __name__ == "__main__":     run2a()     run2b()     run2c()     run2d(sub2)     run2e(sub2)     run2f(sub2)     run2g(sub2) 

python 3.6