Scope in Python 3.6.And the Error -

this question has answer here:

• function not changing global variable 3 answers

how code below give output none?

def funct(x):     x=7  x=11 x=test(x) print(x) 

here code snippet:-

def func():     print (x)     x = 90  x = 1 func() 

the output should 90! scope searched local ,enclosed , global ,build-in .either x should here searched local or global please explain.

x here not global variable in scope of functions, functions naturally create own namespaces, not include outer variables not passed in parameter.

there many issues code, including order of function calling, , order of operations inside functions; answer question in broadest way possible, in order access x variable defined outside of functions, in greater scope is, need reference namespace, prepending global x inside body of each of functions.

read on python variables , scope, , recheck other errors in code have stated above.